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Programming-Idioms

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Idiom #103 Load XML file into struct

Read from the file data.xml and write its contents into the object x.
Assume the XML data is suitable for the type of x. 

(ql:quickload :plump)
(let ((x (plump:parse #p"data.xml")))
  ...)
using System.Xml.Linq;
XDocument x = XDocument.Load("data.xml");


import orange.serialization._;
import orange.serialization.archives._;
import std.file;
XmlArchive archive = new XmlArchive!(char);
archive.doc.parse(read("data.xml"));
Serializer ser = new Serializer(archive);
ser.deserialize(x);
import "encoding/xml"
import "os"
buffer, err := os.ReadFile("data.xml")
if err != nil {
	return err
}
err = xml.Unmarshal(buffer, &x)
if err != nil {
	return err
}
def x = new XmlSlurper().parse(new File('data.xml'))
use XML::LibXML qw();
my $x = XML::LibXML->load_xml(
location => 'data.xml');
import lxml.etree
x = lxml.etree.parse('data.xml')
import scala.xml.XML
val xml = XML.loadFile("data.xml")
New implementation...
< > ⌨
programming-idioms.org 
(let ((x (plump:parse #p"data.xml")))
  ...)
XDocument x = XDocument.Load("data.xml");


XmlArchive archive = new XmlArchive!(char);
archive.doc.parse(read("data.xml"));
Serializer ser = new Serializer(archive);
ser.deserialize(x);
buffer, err := os.ReadFile("data.xml")
if err != nil {
	return err
}
err = xml.Unmarshal(buffer, &x)
if err != nil {
	return err
}
def x = new XmlSlurper().parse(new File('data.xml'))
my $x = XML::LibXML->load_xml(
location => 'data.xml');
x = lxml.etree.parse('data.xml')
val xml = XML.loadFile("data.xml")