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Programming-Idioms

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  • Ruby

Idiom #108 Determine if variable name is defined

Print the value of variable x, but only if x has been declared in this program.
This makes sense in some languages, not all of them. (Null values are not the point, rather the very existence of the variable.)

puts x if defined?(x)
import std.stdio;
static if (is(typeof(x = x.init)))
    writeln(x);

We test, at compile-time, if an assignExpression with x as lhs would compile, if so we use it.

This technic is sometimes used in template constraints, but rather to test if an operation would be accepted on an argument.
New implementation...
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programming-idioms.org 
puts x if defined?(x)
static if (is(typeof(x = x.init)))
    writeln(x);
int x = 42;

void printIfDefined(alias name)()
{
    import std.stdio: writeln;
    static if( __traits(compiles, writeln(mixin(name))))
        writeln(mixin(name));
}

void main(string[] args)
{
    printIfDefined!"x";
    printIfDefined!"Foo.bar";
}
implicit none

print *,x
try {
	console.log(x);
} catch (e) {
	if (!e instanceof ReferenceError) {
		throw e;
	}
}
if (typeof x !== 'undefined') {
    console.log(x);
}
try {
    Class<?> c = getClass();
    Field f = c.getDeclaredField("x");
    out.println(f.get(this));
} catch (NoSuchFieldException e) {

} catch (IllegalAccessException e) {

}
if x then print(x) end
$x = 'foo';

if (isset($x)) {
    echo $x;
}
if(@$foo) print($foo);
{$if DECLARED(x)}
writeln(x);
{$endif}
print $x;  # compile error

print $x if $main::{x}; # prints $x if it was declared


use strict 'vars';
# or
use v5.11; # or higher

print $x if $main::{x};  # unavoidable compile error


try:
    x
except NameError:
    print("does not exist")
if 'x' in locals():
	print(x)