Logo

Programming-Idioms

  • Fortran
  • Java

Idiom #134 Create a new list

Declare and initialize a new list items, containing 3 elements a, b, c.

import java.util.List;
import java.util.ArrayList;
List<T> items = new ArrayList<>();
items.add(a);
items.add(b);
items.add(c);

T is the type of a, b, c.
import java.util.List;
import java.util.Arrays;
List<T> items = Arrays.asList(a, b, c);

T is the type of a, b, c.
import static java.util.List.of;
import java.util.ArrayList;
import java.util.List;
List<T> items = new ArrayList<>(of(a, b, c));

Mutable
import java.util.List;
var items = List.of(a, b, c);

Since Java 9
integer, dimension(3) :: items
items = [a,b,c]
(def items (list a b c))
New implementation...
< > ⌨
programming-idioms.org 
List<T> items = new ArrayList<>();
items.add(a);
items.add(b);
items.add(c);
List<T> items = Arrays.asList(a, b, c);
List<T> items = new ArrayList<>(of(a, b, c));
var items = List.of(a, b, c);
integer, dimension(3) :: items
items = [a,b,c]
(def items (list a b c))
list items { a, b, c };
std::vector<T> items = {a, b, c};
T[] items = new T[] { a, b, c };
var items = new List<T>{a,b,c};
auto items = [a, b, c];
var items = [a, b, c];
items = [a, b, c]
Items = [A,B,C].
items := []T{a, b, c}
def items = [a, b, c]
items = [a, b, c]
const items = new Array(a, b, c);
const items = [a, b, c];
val items = listOf(a, b, c)
(defparameter *items* (list a b c))
items = {a, b, c}
NSArray *items=@[a,b,c];
$items = [$a, $b, $c];
var
  Items: TList;
  a,b,c: pointer;
begin
  Items := TList.Create;
  Items.Add(a);
  Items.Add(b);
  Items.Add(c);
end.
my @items = ($a, $b, $c);
items = [a, b, c]
items = list((a, b, c))
items = [a, b, c]
let items = vec![a, b, c];
val items = List(a, b, c)
(define items (list a b c))
items := {a . b . c}.
Dim salmons As New List(Of String) From
    {"chinook", "coho", "pink", "sockeye"}