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Programming-Idioms

  • JS
  • Python

Idiom #151 Remove string trailing path separator

Remove last character from string p, if this character is the file path separator of current platform.

Note that this also transforms unix root path "/" into the empty string!

import os
if p.endswith(os.sep):
    p = p[:-1]
import * as path from 'path'
p = p.endsWith(path.sep) ? p.slice(0, -path.sep.length) : p
using System.IO;
p.TrimEnd(Path.DirectorySeparatorChar);
New implementation...
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if p.endswith(os.sep):
    p = p[:-1]
p = p.endsWith(path.sep) ? p.slice(0, -path.sep.length) : p
p.TrimEnd(Path.DirectorySeparatorChar);

p = p.chomp(dirSeparator);
if (p.endsWith(path.separator)) p = p.substring(0, p.length - 1);
sep := fmt.Sprintf("%c", filepath.Separator)
p = strings.TrimSuffix(p, sep)
sep := fmt.Sprintf("%c", os.PathSeparator)
p = strings.TrimSuffix(p, sep)
p' = dropWhileEnd (== pathSeparator) p
int n = p.length() - 1;
while (n != 0 && p.charAt(n) == separatorChar)
    p = p.substring(0, n--);
if string.sub(p, -1, -1) == "/" then
	p=string.sub(p, 1, -2)
end
begin
  p := ChompPathDelim(p);
end.
begin
  p := ExcludeTrailingPathDelimiter(p);
end.
chomp $p, File::Spec->catdir('');
p.chomp!("/")
p = p.strip_suffix(std::path::is_separator).unwrap_or(p);
let p = if ::std::path::is_separator(p.chars().last().unwrap()) {
    &p[0..p.len()-1]
} else {
    p
};