Idiom #166 Concatenate two lists
Create the list ab containing all the elements of the list a, followed by all the elements of the list b.
Create the list ab containing all the elements of the list a, followed by all the elements of the list b.
var list1 = new List<int>(){1,2,3};
var list2 = new List<int>(){4,5,6};
var list3 = list1.Concat(list2);
auto ab = a; ab.insert (ab.end (), b.begin (), b.end ());
(def ab (concat a b))
var list1 = new List<int>(){1,2,3}; var list2 = new List<int>(){4,5,6}; var list3 = list1.Concat(list2);
int[] a, b; auto ab = a ~ b;
int[] a, b; auto ab = chain(a, b);
var ab = a + b;
ab = a ++ b
AB = A ++ B.
real, dimension(:), allocatable :: ab ab = [a, b]
ab := append(a, b...)
var ab []T ab = append(append(ab, a...), b...)
ab := make([]T, len(a)+len(b)) copy(ab, a) copy(ab[len(a):], b)
ab = a ++ b
var ab = a.concat(b);
List<?> ab = new ArrayList<>(a) {{ addAll(b); }};
var ab = new ArrayList<>(a); ab.addAll(b);
val ab = a + b
(setf ab (append a b))
ab = {} table.foreach(a, function(k, v) table.insert(ab, v) end) table.foreach(b, function(k, v) table.insert(ab, v) end)
ab = {} table.move(a, 1, #a, 1, ab) table.move(b, 1, #b, #ab + 1, ab)
NSArray *ab=[a arrayByAddingObjectsFromArray:b];
$ab = array_merge($a, $b);
var a,b,ab: TList; ... ab := TList.Create; ab.Assign(a); ab.AddList(b); ...
@ab = (@a, @b)
ab = a + b
ab = list(chain(a, b))
ab = a + b
let ab = [a, b].concat();
val ab = a ::: b
val ab = a ++ b
(define ab (append a b))
ab := a,b