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Programming-Idioms

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  • Java

Idiom #251 Parse binary digits

Extract integer value i from its binary string representation s (in radix 2)
E.g. "1101" -> 13

Integer i = Integer.valueOf(s, 2);

The second argument in the valueOf method denotes the radix, or base, of the said value.
int i = s.chars()
    .map(x -> x - '0')
    .reduce(0, (a, b) -> a * 2 + b);
import java.math.BigInteger;
int i = new BigInteger(s, 2).intValue();
(def i (read-string (str "2r" s)))
New implementation...
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programming-idioms.org 
Integer i = Integer.valueOf(s, 2);
int i = s.chars()
    .map(x -> x - '0')
    .reduce(0, (a, b) -> a * 2 + b);
int i = new BigInteger(s, 2).intValue();
(def i (read-string (str "2r" s)))
int i = std::stoi(s, nullptr, 2);
int i = int.Parse(s, System.Globalization.NumberStyles.BinaryNumber);
var i = int.parse(s, radix: 2);

erlang:list_to_integer(S,2).
character (len=:), allocatable :: s
integer :: i  
s = '1101'
read (s,'(B4)') i

  
i, err := strconv.ParseInt(s, 2, 0)
const i = parseInt(s, 2)
$i = bindec($s);
i := StrToInt('%'+s);
$i = oct('0b' . $s);
i = 0
for x in map(int, s):
    i = i * 2 + x
i = int(s, 2)
i = s.to_i(2)
let i = i32::from_str_radix(s, 2).expect("Not a binary number!");