Idiom #46 Extract beginning of string (prefix)

Create the string t consisting of the 5 first characters of the string s.
Make sure that multibyte characters are properly handled.

def t = s[0..<5]

def t = s.take(5)

T : String := S (1 .. 5);

(def t (apply str (take 5 s)))

IDENTIFICATION DIVISION.
PROGRAM-ID. prefix 5.
PROCEDURE DIVISION.
    MOVE s(1:5) TO t 	
STOP RUN.

auto t = s.substr(0, 5);

string t = s.Substring(0, 5);

string t = s[0..5];

var t = s.substring(0, 5);

t = String.slice(s, 0, 5)

[A, B, C, D, E | _] = S,
T = [A, B, C, D, E].

T = string:slice(S, 0, 5).

 character(len=5) :: t
 t = s(1:5)

t := s
r := []rune(s)
if len(r) > 5 {
	t = string(r[:5])
}

i := 0
count := 0
for i = range s {
	if count >= 5 {
		break
	}
	count++
}
t := s
if count >= 5 {
	t = s[:i]
}

import qualified Data.Text as T

t :: T.Text
t = T.take 5 s

t :: String
t = take 5 s

let t = s.substring(0,5);

String t = s.substring(0,5);

val t = s.take(5)

(setf *t* (subseq s 0 5))

t = s:sub(1,5)

@import Foundation;

NSString *t=[s substringToIndex:5];

$t = mb_substr($s, 0, 5, 'UTF-8');

_t := Copy(_s, 1, 5);

my $t = substr($s,0,5);

t = s[:5]

t = s.slice(0, 5)

t = s.slice(0...5)

t = s[0, 5]

let t = s.char_indices().nth(5).map_or(s, |(i, _)| &s[..i]);

let t = s.chars().take(5).collect::<String>();

val t = s.take(5)

s first: 5

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Idiom created by programming-idioms.org

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