Idiom #77 Complex number

Declare a complex x and initialize it with value (3i - 2). Then multiply it by i.

extern crate num;
use num::Complex;

let mut x = Complex::new(-2, 3);
x *= Complex::i();

with Ada.Numerics.Complex_Types;

declare
   use Ada.Numerics.Complex_Types;
   X : Complex := (Re => -2.0, Im => 3.0);
begin
   X := X * i;
end;

#include <complex.h>

float complex _x = -2 + 3 * I;

_x *= I;

#include <complex>

using namespace std::complex_literals;
	
auto x = 3i - 2.;
x *= 1i;

System.Numerics;

var x = new Complex(-2, 3);
x *= Complex.ImaginaryOne;

import std.complex;

auto x = complex(-2, 3);
x * complex(0, 1);

  complex :: x
  x = (-2,3)
  x = x * (0,1)

x := 3i - 2
x *= 1i

ímport Data.Complex

x = (0 :+ 1) * ((0 - 2) :+ 3)

let i = ( 0 :+ 1 ) ; x = 3 * i - 2 in x * i

var math = require('mathjs');

var x = math.complex(-2, 3);
x = math.multiply(x, math.i);

import org.apache.commons.math4.complex.Complex;

Complex x = new Complex(-2.0, 3.0);
x = x.multiply(Complex.I);

(let ((x #c(-2 3)))
  (* x #c(0 1)))

uses ucomplex;

var
  C: Complex;
begin
  C := 3*i - 2;
end.

use Math::Complex;

my $x = cplx(-2, 3);
$x *= i;

use Math::Complex;

my $x = 3*i - 2;
$x *= i;

x = 3j-2
y = x * 1j

x = 3i - 2
x *= 1i

(define x -2+3i)
(display (* x 0+1i))

Do you know the best way to do this in your language ? New implementation...

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Idiom created by deleplace

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