Idiom #227 Copy a list

Create the new list y containing the same elements as the list x.

Subsequent modifications of y must not affect x (except for the contents referenced by the elements themselves if they contain pointers).

Perl

use Storable qw(dclone);

my @y = @x; # for simple arrays

# for complex arrays with references:
my @y = @{dclone(\@x)};

Demo
Doc

List<T> y = x.ToList();

List<Int32> y = new List<Int32>(x);

y = [...x];

type (foo), allocatable, dimension(:) :: y
y = x

import "slices"

y := slices.Clone(x)

Demo
Doc

y := make([]T, len(x))
copy(y, x)

Demo
Doc

let y = x.slice();

Doc
Origin

import java.util.ArrayList;

List<T> y = new ArrayList<>(x);

local function deepcopy(input)
 local t=type(input)
 if t~="table" then
  return input
 end
 local copy={}
 for k,v in pairs(input) do
  k=deepcopy(k)
  v=deepcopy(v)
  copy[k]=v
 end
 return copy
end
local y=deepcopy(x)