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Python Lua
1
Print a literal string on standard output
print("Hello World")
Alternative implementation:
print('Hello World')
print("Hello World")
Alternative implementation:
io.write("Hello world")
2
Loop to execute some code a constant number of times
for _ in range(10):
    print("Hello")
Alternative implementation:
print("Hello\n"*10)
Alternative implementation:
i = 0
while i < 10:
    print('Hello')
    i += 1
Alternative implementation:
def f(): print('Hello')
for x in range(10): f()
Alternative implementation:
f = lambda: print('Hello')
for x in range(10): f()
Alternative implementation:
for x in repeat('Hello', 10): print(x)
for i=1, 10 do
	print('Hello')
end
Alternative implementation:
print(("Hello\n"):rep(10))
Alternative implementation:
print(string.rep("Hello\n", 10))
Alternative implementation:
local i = 0
repeat
	i = i + 1
	print("Hello")
until i == 10
3
Like a function which doesn't return any value, thus has only side effects (e.g. Print to standard output)
def finish(name):
    print(f'My job here is done. Goodbye {name}')
Alternative implementation:
f = lambda: print('abc')
f()
function finish(name)
	print('My job here is done. Goodbye, '..name..'.')
end
4
Create a function which returns the square of an integer
def square(x):
    return x*x
Alternative implementation:
def square(x):
    return x**2
Alternative implementation:
square = lambda x: x * x
function square(x)
	return x*x
end
5
Declare a container type for two floating-point numbers x and y
@dataclass
class Point:
    x: float
    y: float
Alternative implementation:
Point = namedtuple("Point", "x y")
Alternative implementation:
point = {'x': 1.2, 'y': 3.4}
Alternative implementation:
class P:
    def __init__(self, x: float, y: float):
        self.x, self.y = x, y
Alternative implementation:
point = dict(x=1.2, y=3.4)
point = { x = 123, y = 456 }
6
Do something with each item x of the list (or array) items, regardless indexes.
for x in items:
        doSomething( x )
Alternative implementation:
[do_something(x) for x in items]
for _, x in ipairs(items) do
	print(x)
end
7
Print each index i with its value x from an array-like collection items
for i, x in enumerate(items):
    print(i, x)
Alternative implementation:
for x in enumerate(items): print(x)
for i, x in ipairs(items) do
	print('Index: '..i..', Value: '..x)
end
8
Create a new map object x, and provide some (key, value) pairs as initial content.
x = {"one" : 1, "two" : 2}
Alternative implementation:
x = dict(a=1, b=2, c=3)
x = {one = 1, two = 2}
9
The structure must be recursive because left child and right child are binary trees too. A node has access to children nodes, but not to its parent.
class Node:
	def __init__(self, data):
		self.data = data
		self.left = None
		self.right = None
Alternative implementation:
class Node:
  def __init__(self, data, left_child, right_child):
    self.data = data
    self._left_child = left_child
    self._right_child = right_child
local function BinTree(v, l, r)
	return {
		val = v,
		left = l,
		right = r
	}
end
10
Generate a random permutation of the elements of list x
shuffle(x)
Alternative implementation:
random.shuffle(x)
shuffled = {}
for i, v in ipairs(x) do
	local pos = math.random(1, #shuffled+1)
	table.insert(shuffled, pos, v)
end
Alternative implementation:
function(x)
	for i = #x, 2, -1 do
		local j = math.random(i)
		x[i], x[j] = x[j], x[i]
	end
end
11
The list x must be non-empty.
random.choice(x)
x[math.random(#x)]
12
Check if the list contains the value x.
list is an iterable finite container.
x in list
function contains(list, x)
	for _, v in ipairs(list) do
		if v == x then return true end
	end
	return false
end
13
Access each key k with its value x from an associative array mymap, and print them.
for k, v in mymap.items():
    print(k, v)
Alternative implementation:
for x in mymap.items(): print(x)
for k, x in pairs(mymap) do
	print('Key: '..k..', Value: '..x)
end
14
Pick a random number greater than or equals to a, strictly inferior to b. Precondition : a < b.
random.uniform(a,b)
function pick(a,b)
	return a + (math.random()*(b-a))
end
15
Pick a random integer greater than or equals to a, inferior or equals to b. Precondition : a < b.
random.randint(a,b)
math.random(a, b)
16
Call a function f on every node of binary tree bt, in depth-first infix order
def dfs(bt):
	if bt is None:
		return
	dfs(bt.left)
	f(bt)
	dfs(bt.right)
local function dfs(bt, f, ...)
  local tt = type(bt)
  if tt~='table' and tt~='userdata' then return end
  dfs(t.left, f, ...)
  f(t.data, ...)
  dfs(t.right, f, ...)
end
17
The structure must be recursive. A node may have zero or more children. A node has access to its children nodes, but not to its parent.
class Node:
    def __init__(self, value, *children):
        self.value = value
        self.children = list(children)
local function Tree(v, c)
	return {
		val = v,
		children = c
	}
end
18
Call a function f on every node of a tree, in depth-first prefix order
def DFS(f, root):
	f(root)
	for child in root:
		DFS(f, child)
19
Reverse the order of the elements of the list x.
This may reverse "in-place" and destroy the original ordering.
x = reversed(x)
Alternative implementation:
y = x[::-1]
Alternative implementation:
x.reverse()
rev = {}
for i=#x, 1, -1 do
	rev[#rev+1] = x[i]
end
x = rev
Alternative implementation:
rev = {}
for i=#x, 1, -1 do
	rev[#rev+1] = x[i]
end

-- in-situ reversal
function reverse(t)
  local n = #t
  local i = 1
  for i = 1, n do
    t[i],t[n] = t[n],t[i]

    n = n - 1
  end
end
Alternative implementation:
function array_reverse(x)
  local n, m = #x, #x/2
  for i=1, m do
    x[i], x[n-i+1] = x[n-i+1], x[i]
  end
  return x
end
20
Implement a function search which looks for item x in a 2D matrix m.
Return indices i, j of the matching cell.
Think of the most idiomatic way in the language to return the two values at the same time.
def search(m, x):
    for idx, item in enumerate(m):
        if x in item:
            return idx, item.index(x)
Alternative implementation:
def search(x, m):
    for i, M in enumerate(m):
        for j, N in enumerate(M):
            if N == x: return (i, j)
function search(m, x)
   for i,v1 in ipairs(m) do
      for j,v2 in ipairs(v1) do
         if v2 == x then return i,j end
      end
   end
end
21
Swap the values of the variables a and b
a, b = b, a
Alternative implementation:
a =int(input("enter a number"))
b =int(input("enter b number")) 
a, b = b, a
 
print("Value of a:", a)
print("Value of a", b)
a, b = b, a
22
Extract the integer value i from its string representation s (in radix 10)
i = int(s)
i = tonumber(s)
23
Given a real number x, create its string representation s with 2 decimal digits following the dot.
s =  '{:.2f}'.format(x)
Alternative implementation:
s = f'{x:.2f}'
s = string.format("%.2f",x)
24
Declare a new string s and initialize it with the literal value "ネコ" (which means "cat" in japanese)
s = "ネコ"
s = 'ネコ'
25
Share the string value "Alan" with an existing running process which will then display "Hello, Alan"
q = Queue()

def worker():
    while True:
        print(f"Hello, {q.get()}")
        q.task_done()

Thread(target=worker, daemon=True).start()

q.put("Alan")
q.join()
26
Declare and initialize a matrix x having m rows and n columns, containing real numbers.
x = [[0] * n for _ in range(m)]
local x = setmetatable({},{
   __index = function(t1,k1)
      t1[k1] = setmetatable({},{
         __index = function(t2,k2)
            t2[k2] = 0
            return t2[k2]
         end
      })
      return t1[k1]
   end
})
Alternative implementation:
x = {}
for i=1,m do
  x[i] = {}
  for j=1,n do
    x[i][j] = 0
  end
end
27
Declare and initialize a 3D array x, having dimensions boundaries m, n, p, and containing real numbers.
x = [[[0 for k in range(p)] for j in range(n)] for i in range(m)]
Alternative implementation:
x = numpy.zeros((m,n,p))
local x = {}
for i=1,m do
   x[i] = {}
   for j=1,n do
      x[i][j] = {}
      for k=1,p do
         x[i][j][k] = 0
      end
   end
end
28
Sort the elements of the list (or array-like collection) items in ascending order of x.p, where p is a field of the type Item of the objects in items.
items = sorted(items, key=lambda x: x.p)
Alternative implementation:
items = sorted(items, key=attrgetter('p'))
table.sort(items, function(a,b)
	if a.p < b.p then return true end
end)
29
Remove i-th item from list items.
This will alter the original list or return a new list, depending on which is more idiomatic.
Note that in most languages, the smallest valid value for i is 0.
del items[i]
Alternative implementation:
items.pop(i)
local removedItem = table.remove(items,i)
30
Launch the concurrent execution of procedure f with parameter i from 1 to 1000.
Tasks are independent and f(i) doesn't return any value.
Tasks need not run all at the same time, so you may use a pool.
pool = Pool()
for i in range(1, 1001):
	pool.apply_async(f, [i])
31
Create the recursive function f which returns the factorial of the non-negative integer i, calculated from f(i-1)
def f(i):
   if i == 0:
       return 1
   else:
       return i * f(i-1)
function f(n)
   local function f_(factorial,n)
      if n < 2 then return 1
      return f_(factorial*n, n-1)
   end
   return f_(1,n)
end
32
Create function exp which calculates (fast) the value x power n.
x and n are non-negative integers.
def exp(x, n):
        return x**n
function exp(x, n)
    return x^n
end
33
Assign to the variable x the new value f(x), making sure that no other thread may modify x between the read and the write.
lock = threading.Lock()

lock.acquire()
try:
	x = f(x)
finally:
	lock.release()
Alternative implementation:
with threading.Lock():
    x = f(x)
34
Declare and initialize a set x containing unique objects of type T.
class T(object):
    pass

x = set(T())
Alternative implementation:
class T:
   ...

s = set(T() for _ in range(x))
35
Implement a function compose (A -> C) with parameters f (A -> B) and g (B -> C), which returns the composition function g ∘ f
def compose(f, g):
    return lambda a: g(f(a))
function compose(f,g)
   return function(x)
      return g(f(x))
   end
end
36
Implement a function compose which returns composition function g ∘ f for any functions f and g having exactly 1 parameter.
def compose(f, g):
	return lambda x: g(f(x))
Alternative implementation:
compose = lambda f, g, x: g(f(x))
function compose(f,g)
   return function(x)
      return g(f(x))
   end
end
37
Transform a function that takes multiple arguments into a function for which some of the arguments are preset.
def add(a, b):
	return a+b

add_to_two = partial(add, 2)
function curry2(f)
   return function(a)
      return function(b)
         return f(a,b)
      end
   end
end

function add(a,b)
   return a + b
end

local curryAdd = curry2(add)
local add2 = curryAdd(2)
Alternative implementation:
local unpack = unpack or table.unpack
local function aux_ncurry(n, m, fn, args)
  if m>n then return fn(unpack(args,1,n))end
  local new_args, new_m = {}, m
  for i=1,m-1 do new_args[i]=args[i]end
  return function(a) 
    new_args[new_m]=a
    return aux_ncurry(n, new_m + 1, fn, new_args)
  end
end
local function ncurry(n, fn) return aux_ncurry(n,1,fn,{}) end
38
Find substring t consisting in characters i (included) to j (excluded) of string s.
Character indices start at 0 unless specified otherwise.
Make sure that multibyte characters are properly handled.
t = s[i:j]
Alternative implementation:
t = s[slice(i, j)]
local t = s:sub(i, j - 1)
39
Set the boolean ok to true if the string word is contained in string s as a substring, or to false otherwise.
ok = word in s
ok = s:find(word, 1, true)
Alternative implementation:
ok = false
if s:find(word, 1, true) then ok = true end
Alternative implementation:
ok = s:find(word, 1, true) ~= nil
40
Declare a Graph data structure in which each Vertex has a collection of its neighbouring vertices.
class Vertex(set): pass
class Graph(defaultdict):
  def __init__(self, *paths):
    self.default_factory = Vertex
    for path in paths:
      self.make_path(path)

  def make_path(self, labels):
    for l1, l2 in zip(labels, labels[1:]):
      self[l1].add(l2)
      self[l2].add(l1)

G = Graph((0, 1, 2, 3), (1, 4, 2))
41
Create the string t containing the same characters as the string s, in reverse order.
The original string s must remain unaltered. Each character must be handled correctly regardless its number of bytes in memory.
t = s[::-1]
Alternative implementation:
t = ''.join(reversed(s))
function utf8.reverse(s)
	local r = ""
	for p,c in utf8.codes(s) do
		r = utf8.char(c)..r
	end
	return r
end

t = utf8.reverse(s)
42
Print each item v of list a which is not contained in list b.
For this, write an outer loop to iterate on a and an inner loop to iterate on b.
for v in a:
    try:
        for u in b:
            if v == u:
                raise Exception()
        print(v)
    except Exception:
        continue
Alternative implementation:
for v in a:
  keep = True
  for w in b:
    if w == v:
      keep = False
      break
  if keep:
    print(v)
43
Look for a negative value v in 2D integer matrix m. Print it and stop searching.
class BreakOuterLoop (Exception): pass

try:
    position = None
    for row in m:
        for column in m[row]:
            if m[row][column] == v:
                position = (row, column)
                raise BreakOuterLoop
except BreakOuterLoop:
    pass
Alternative implementation:
def loop_breaking(m, v): 
    for i, row in enumerate(m): 
        for j, value in enumerate(row): 
            if value == v: 
                return (i, j)
    return None

print(loop_breaking(([1,2,3],[4,5,6],[7,8,9]), 6))
Alternative implementation:
matrix = [[1,2,3],[4,-5,6],[7,8,9]]
try:
    print(next(i for i in chain.from_iterable(matrix) if i < 0))
except StopIteration:
    pass
Alternative implementation:
b = False
for r in m:
    for i in r:
        if i < 0:
            print(i)
            b = True
    if b: break
Alternative implementation:
b = False
for r in m:
    for i in r:
        if i < 0:
            print(i)
            b = True
    if b: break
breakout = false
for i,v1 in ipairs(m) do
   for j,v2 in ipairs(v1) do
      if v2 < 0 then
         print(v2)
         state = "found"
         breakout = true
         break
      end
   end
   if breakout then break end
end
Alternative implementation:
for _,v1 in ipairs(m) do
 for _,v2 in ipairs(v1) do
  if v2<0 then
   print(v2)
   goto outer
  end
 end
end
::outer::
44
Insert the element x at position i in the list s. Further elements must be shifted to the right.
s.insert(i, x)
table.insert(s,i,x)
45
Sleep for 5 seconds in current thread, before proceeding with the next instructions.
time.sleep(5)
local start = os.clock()
while os.clock() - start < 5 do end
Alternative implementation:
os.execute(package.config:sub(1,1) == "/" and "sleep 5" or "timeout 5")
46
Create the string t consisting of the 5 first characters of the string s.
Make sure that multibyte characters are properly handled.
t = s[:5]
t = s:sub(1,5)
47
Create string t consisting in the 5 last characters of string s.
Make sure that multibyte characters are properly handled.
t = s[-5:]
48
Assign to variable s a string literal consisting in several lines of text, including newlines.
s = """Huey
Dewey
Louie"""
s = [[
Huey
Dewey
Louie
]]
Alternative implementation:
s = 'Huey \n'..
'Dewey \n'..
'Louie'
49
Build list chunks consisting in substrings of the string s, separated by one or more space characters.
chunks = s.split()
Alternative implementation:
chunks = split(' +', s)
chunks = {}
for substring in s:gmatch("%S+") do
   table.insert(chunks, substring)
end
50
Write a loop that has no end clause.
while True:
    pass
Alternative implementation:
while 1: ...
while true do 
	-- Do something
end
Alternative implementation:
::loop::
goto loop
Alternative implementation:
repeat
until false
51
Determine whether the map m contains an entry for the key k
k in m
Alternative implementation:
m.get(k)
m[k] ~= nil
52
Determine whether the map m contains an entry with the value v, for some key.
v in m.values()
53
Concatenate elements of string list x joined by the separator ", " to create a single string y.
y = ', '.join(x)
Alternative implementation:
y = ', '.join(map(str, x))
Alternative implementation:
f = lambda a, b: f'{a}, {b}'
y = reduce(f, x)
y = table.concat(x, ", ")
54
Calculate the sum s of the integer list or array x.
s = sum(x)
s = 0
for i,v in ipairs(x) do
   s = s + v
end
55
Create the string representation s (in radix 10) of the integer value i.
s = str(i)
s = tostring(i)
56
Fork-join : launch the concurrent execution of procedure f with parameter i from 1 to 1000.
Tasks are independent and f(i) doesn't return any value.
Tasks need not run all at the same time, so you may use a pool.
Wait for the completion of the 1000 tasks and then print "Finished".
def f(i):
	i * i

with Pool(1000) as p:
	p.map(func=f, iterable=range(1, 1001))

print('Finished')
57
Create the list y containing the items from the list x that satisfy the predicate p. Respect the original ordering. Don't modify x in-place.
y = list(filter(p, x))
Alternative implementation:
y = [element for element in x if p(element)]
y = {}
for _, v in ipairs(x) do
	if p(v) then y[#y+1] = v end
end
Alternative implementation:
local y={}
for _,v in ipairs(x) do
 if p(v)==true then 
  table.insert(y,v)
 end
end
58
Create the string lines from the content of the file with filename f.
lines = open(f).read()
Alternative implementation:
with open(f) as fo:
    lines = fo.read()
lines = io.input(f):read('a')
59
Print the message "x is negative" to standard error (stderr), with integer x value substitution (e.g. "-2 is negative").
print(x, "is negative", file=sys.stderr)
io.stderr:write(string.format("%d is negative\n",x))
60
Assign to x the string value of the first command line parameter, after the program name.
x = sys.argv[1]
x = arg[1]
61
Assign to the variable d the current date/time value, in the most standard type.
d = datetime.datetime.now()
d = os.date()
62
Set i to the first position of string y inside string x, if exists.

Specify if i should be regarded as a character index or as a byte index.

Explain the behavior when y is not contained in x.
i = x.find(y)
i = x:find(y)
63
Assign to x2 the value of string x with all occurrences of y replaced by z.
Assume occurrences of y are not overlapping.
x2 = x.replace(y, z)
x2 = x:gsub(y,z)
64
Assign to x the value 3^247
x = 3 ** 247
65
From the real value x in [0,1], create its percentage string representation s with one digit after decimal point. E.g. 0.15625 -> "15.6%"
s = '{:.1%}'.format(x)
Alternative implementation:
s = f"{x:.01%}"
s = string.format("%.1f%%", x*100)
Alternative implementation:
local s = (x-x%10^-3)*100 .."%"
66
Calculate the result z of x power n, where x is a big integer and n is a positive integer.
z = x**n
67
Calculate binom(n, k) = n! / (k! * (n-k)!). Use an integer type able to handle huge numbers.
def binom(n, k):
    return math.factorial(n) // math.factorial(k) // math.factorial(n - k)
Alternative implementation:
def binom(n, k):
    return math.comb(n, k)
68
Create an object x to store n bits (n being potentially large).
x = bytearray(int(math.ceil(n / 8.0)))
69
Use seed s to initialize a random generator.

If s is constant, the generator output will be the same each time the program runs. If s is based on the current value of the system clock, the generator output will be different each time.
rand = random.Random(s)
math.randomseed(s)
70
Get the current datetime and provide it as a seed to a random generator. The generator sequence will be different at each run.
rand = random.Random()
math.randomseed( os.time() )
71
Basic implementation of the Echo program: Print all arguments except the program name, separated by space, followed by newline.
The idiom demonstrates how to skip the first argument if necessary, concatenate arguments as strings, append newline and print it to stdout.
print(' '.join(sys.argv[1:]))
print( table.concat( arg, " " ) )
73
Create a factory named fact for any sub class of Parent and taking exactly one string str as constructor parameter.
def fact(a_class, str_):
    if issubclass(a_class, Parent):
        return a_class(str_)
74
Compute the greatest common divisor x of big integers a and b. Use an integer type able to handle huge numbers.
x = gcd(a, b)
Alternative implementation:
x = math.gcd(a, b)
function gcd(x, y)
	if (y == 0) then
		return x
	else 
		return gcd(y, x%y)
	end
end
Alternative implementation:
function gcd(a, b)
	return b==0 and a or gcd(b,a%b)
end
75
Compute the least common multiple x of big integers a and b. Use an integer type able to handle huge numbers.
x = (a*b)//gcd(a, b)
Alternative implementation:
x = math.lcm(a, b)
76
Create the string s of integer x written in base 2.

E.g. 13 -> "1101"
s = '{:b}'.format(x)
Alternative implementation:
s = format(x, 'b')
local s = {}

while x > 0 do
    local tmp = math.fmod(x,2)
    s[#s+1] = tmp
    x=(x-tmp)/2
end

s=table.concat(s)
77
Declare a complex x and initialize it with value (3i - 2). Then multiply it by i.
x = 3j-2
y = x * 1j
78
Execute a block once, then execute it again as long as boolean condition c is true.
while True:
    do_something()
    if not c:
        break
repeat
	someThing()
	someOtherThing()
until not c
79
Declare the floating point number y and initialize it with the value of the integer x .
y = float(x)
y = x + .0
Alternative implementation:
y = (16 ^ 13) + x - (16 ^ 13)
80
Declare integer y and initialize it with the value of floating point number x . Ignore non-integer digits of x .
Make sure to truncate towards zero: a negative x must yield the closest greater integer (not lesser).
y = int(x)
y = math.modf(x)
81
Declare the integer y and initialize it with the rounded value of the floating point number x .
Ties (when the fractional part of x is exactly .5) must be rounded up (to positive infinity).
y = int(x + 0.5)
Alternative implementation:
c = Context(rounding=ROUND_HALF_UP)
y = round(Decimal(x, c))
function round(float)
    local int, part = math.modf(float)
    if float == math.abs(float) and part >= .5 then return int+1    -- positive float
    elseif part <= -.5 then return int-1                            -- negative float
    end
    return int
end
Alternative implementation:
function round(float)
    return math.floor(float + .5)
end
82
Find how many times string s contains substring t.
Specify if overlapping occurrences are counted.
count = s.count(t)
83
Declare the regular expression r matching the strings "http", "htttp", "httttp", etc.
r = re.compile(r"htt+p")
r = "htt+p"
84
Count number c of 1s in the integer i in base 2.

E.g. i=6 → c=2
c = bin(i).count("1")
Alternative implementation:
c = i.bit_count()
85
Write boolean function addingWillOverflow which takes two integers x, y and return true if (x+y) overflows.

An overflow may be above the max positive value, or below the min negative value.
def adding_will_overflow(x,y):
    return False
local function intadding_will_overflow(x,y)
 return x>0
  and y>0 and x+y<x
  or y<0 and x+y>x
end
86
Write the boolean function multiplyWillOverflow which takes two integers x, y and returns true if (x*y) overflows.

An overflow may reach above the max positive value, or below the min negative value.
def multiplyWillOverflow(x,y):
	return False
87
Exit immediately.
If some extra cleanup work is executed by the program runtime (not by the OS itself), describe it.
sys.exit(1)
os.exit()
Alternative implementation:
return
88
Create a new bytes buffer buf of size 1,000,000.
buf = bytearray(1000000)
89
You've detected that the integer value of argument x passed to the current function is invalid. Write the idiomatic way to abort the function execution and signal the problem.
raise ValueError("x is invalid")
return nil, "Invalid argument x"
Alternative implementation:
error("Invalid argument x")
90
Expose a read-only integer x to the outside world while being writable inside a structure or a class Foo.
class Foo(object):
    def __init__(self):
        self._x = 0

    @property
    def x(self):
        """
        Doc for x
        """
        return self._x
local Foo = {}
do
	local x = 0
	Foo.getX = function()
		return x
	end
end
print(Foo.getX()) -- 0
print(x) -- nil
Alternative implementation:
local function Foo()
    local private = {x = 9}
    local mt = {
        __index = private,
        __newindex = function (t, k, v)
            error("attempt to update a read-only table", 2)
        end
    }
    return setmetatable({}, mt)
end

local foo = Foo()
print(foo.x) -- 9
foo.x = 3    -- error: attempt to update a read-only table
91
Read from the file data.json and write its content into the object x.
Assume the JSON data is suitable for the type of x.
with open("data.json", "r") as input:
    x = json.load(input)
file = io.open("data.json")
x = cjson.decode(file:read("a"))
file:close()
92
Write the contents of the object x into the file data.json.
with open("data.json", "w") as output:
    json.dump(x, output)
file = io.open("data.json", "w")
file:write(cjson.encode(x))
file:close()
93
Implement the procedure control which receives one parameter f, and runs f.
def control(f):
    f()
Alternative implementation:
def control(f: Callable): f()
function control(f)
	f()
end
94
Print the name of the type of x. Explain if it is a static type or dynamic type.

This may not make sense in all languages.
print(type(x))
Alternative implementation:
print(x.__class__)
print(type(x))
95
Assign to variable x the length (number of bytes) of the local file at path.
x = os.path.getsize(path)
96
Set the boolean b to true if string s starts with prefix prefix, false otherwise.
b = s.startswith(prefix)
b = s:find(prefix, 1, true) == 1
Alternative implementation:
function startswith(text, prefix)
    return text:find(prefix, 1, true) == 1
end

b = startswith(s, prefix)
Alternative implementation:
b = string.sub(s, 1, #prefix) == prefix
97
Set boolean b to true if string s ends with string suffix, false otherwise.
b = s.endswith(suffix)
b = s:sub(-string.len(suffix)) == suffix
98
Convert a timestamp ts (number of seconds in epoch-time) to a date with time d. E.g. 0 -> 1970-01-01 00:00:00
d = datetime.date.fromtimestamp(ts)
99
Assign to the string x the value of the fields (year, month, day) of the date d, in format YYYY-MM-DD.
d = date(2016, 9, 28)
x = d.strftime('%Y-%m-%d')
Alternative implementation:
d = date.today()
x = d.isoformat()
x = os.date("%F",d)
100
Sort elements of array-like collection items, using a comparator c.
items.sort(key=c)
Alternative implementation:
items.sort(key=functools.cmp_to_key(c))
table.sort(items,c)
101
Make an HTTP request with method GET to the URL u, then store the body of the response in the string s.
with urllib.request.urlopen(u) as f:
    s = f.read()
Alternative implementation:
s = requests.get(u).content.decode()
102
Make an HTTP request with method GET to the URL u, then store the body of the response in the file result.txt. Try to save the data as it arrives if possible, without having all its content in memory at once.
filename, headers = urllib.request.urlretrieve(u, 'result.txt')
Alternative implementation:
with open("results.txt", "wb") as fh:
	fh.write(requests.get(u).content)
103
Read from the file data.xml and write its contents into the object x.
Assume the XML data is suitable for the type of x.
x = lxml.etree.parse('data.xml')
105
1
s = sys.argv[0]
s = arg[0]
106
Assign to string dir the path of the working directory.
(This is not necessarily the folder containing the executable itself)
dir = os.getcwd()
dir = os.getenv("PWD") or io.popen("cd"):read()
107
Assign to string dir the path of the folder containing the currently running executable.
(This is not necessarily the working directory, though.)
dir = os.path.dirname(os.path.abspath(__file__))
Alternative implementation:
dir = str(Path(__file__).parent)
dir = arg[1]
108
Print the value of variable x, but only if x has been declared in this program.
This makes sense in some languages, not all of them. (Null values are not the point, rather the very existence of the variable.)
if 'x' in locals():
	print(x)
Alternative implementation:
try:
    x
except NameError:
    print("does not exist")
if x then print(x) end
109
Set n to the number of bytes of a variable t (of type T).
n = pympler.asizeof.asizeof(t)
110
Set the boolean blank to true if the string s is empty, or null, or contains only whitespace ; false otherwise.
blank = not s or s.isspace()
 blank = (s == nil or #string.gsub(s, "^%s*(.-)%s*$", "%1") == 0)
111
From current process, run program x with command-line parameters "a", "b".
subprocess.call(['x', 'a', 'b'])
os.execute(x .. 'a b')
112
Print each key k with its value x from an associative array mymap, in ascending order of k.
for k in sorted(mymap):
    print(mymap[k])
Alternative implementation:
for e in sorted(m.items()):
    print(e)
for k, x in pairs(mymap) do
  print(k, x)
end
113
Print each key k with its value x from an associative array mymap, in ascending order of x.
Multiple entries may exist for the same value x.
for x, k in sorted((x, k) for k,x in mymap.items()):
    print(k, x)
Alternative implementation:
for key, value in sorted(d.items(), key=operator.itemgetter(1)):
    print(key, value)
114
Set boolean b to true if objects x and y contain the same values, recursively comparing all referenced elements in x and y.
Tell if the code correctly handles recursive types.
b = x == y
115
Set boolean b to true if date d1 is strictly before date d2 ; false otherwise.
b = d1 < d2
116
Remove all occurrences of string w from string s1, and store the result in s2.
s2 = s1.replace(w, '')
s2 = s1:gsub(w,"")
117
Set n to the number of elements of the list x.
n = len(x)
local n = #x
118
Create the set y from the list x.
x may contain duplicates. y is unordered and has no repeated values.
y = set(x)
local hash = {}
local y = {}
for _,v in ipairs(x) do
   if (not hash[v]) then
       y[#y+1] = v
       hash[v] = true
   end
end
119
Remove duplicates from the list x.
Explain if the original order is preserved.
x = list(set(x))
Alternative implementation:
x = list(OrderedDict(zip(x, x)))
Alternative implementation:
def dedup(x):
  y = []
  for i in x:
    if not i in y:
      y.append(i)
  return y
local seen = {}
for index,item in ipairs(x) do
	if seen[item] then
		table.remove(x, index)
	else
		seen[item] = true
	end
end
120
Read an integer value from the standard input into the variable n
n = int(input("Input Prompting String: "))
n = io.read("n")
121
Listen UDP traffic on port p and read 1024 bytes into the buffer b.
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.bind((UDP_IP, p))
while True:
    data, addr = sock.recvfrom(1024)
    print("received message:", data)
122
Create an enumerated type Suit with 4 possible values SPADES, HEARTS, DIAMONDS, CLUBS.
class Suit:
	SPADES, HEARTS, DIAMONDS, CLUBS = range(4)
Alternative implementation:
class Suit(Enum):
	SPADES = 1
	HEARTS = 2
	DIAMONDS = 3
	CLUBS = 4
Suit = {
    SPADES=1,
    HEARTS=2,
    DIAMONDS=3,
    CLUBS=4
}
123
Verify that predicate isConsistent returns true, otherwise report assertion violation.
Explain if the assertion is executed even in production environment or not.
assert isConsistent
assert(isConsistent() , "Assertion violation") 
124
Write the function binarySearch which returns the index of an element having the value x in the sorted array a, or -1 if no such element exists.
def binarySearch(a, x):
    i = bisect.bisect_left(a, x)
    return i if i != len(a) and a[i] == x else -1
125
measure the duration t, in nanoseconds, of a call to the function foo. Print this duration.
t1 = time.perf_counter_ns()
foo()
t2 = time.perf_counter_ns()
print('Nanoseconds:', t2 - t1)
126
Write a function foo that returns a string and a boolean value.
def foo():
    return 'string', True
Alternative implementation:
foo = lambda: ('abc', True)
function foo()
	return "bar", false
end
127
Import the source code for the function foo body from a file "foobody.txt".
foo = imp.load_module('foobody', 'foobody.txt').foo
128
Call a function f on every node of a tree, in breadth-first prefix order
def BFS(f, root):
	Q = [root]
	while Q:
		n = Q.pop(0)
		f(n)
		for child in n:
			if not n.discovered:
				n.discovered = True
				Q.append(n)
129
Call the function f on every vertex accessible from the vertex start, in breadth-first prefix order
def breadth_first(start, f):
  seen = set()
  q = deque([start])
  while q:
    vertex = q.popleft()
    f(vertex)
    seen.add(vertex)
    q.extend(v for v in vertex.adjacent if v not in seen)
130
Call th function f on every vertex accessible from the vertex v, in depth-first prefix order
def depth_first(start, f):
  seen = set()
  stack = [start]
  while stack:
    vertex = stack.pop()
    f(vertex)
    seen.add(vertex)
    stack.extend(
      v for v in vertex.adjacent if v not in seen
    )
131
Execute f1 if condition c1 is true, or else f2 if condition c2 is true, or else f3 if condition c3 is true.
Don't evaluate a condition when a previous condition was true.
f1() if c1 else f2() if c2 else f3() if c3 else None
Alternative implementation:
if c1:
    f1()
elif c2:
    f2()
elif c3:
    f3()
Alternative implementation:
if c1: f1()
elif c2: f2()
elif c3: f3()
if (c1) then f1()
elseif (c2) then f2()
elseif (c3) then f3()
end
132
Run the procedure f, and return the duration of the execution of f.
duration = timeit.timeit("f()", setup="from __main__ import f")
Alternative implementation:
start = time.time()
f()
end = time.time()
return end - start
133
Set boolean ok to true if string word is contained in string s as a substring, even if the case doesn't match, or to false otherwise.
ok = word.lower() in s.lower()
ok = string.find(string.lower(s), string.lower(word)) and true or false
Alternative implementation:
local ok=string.find(string.lower(s),string.lower(word),nil,true)~=nil
134
Declare and initialize a new list items, containing 3 elements a, b, c.
items = [a, b, c]
Alternative implementation:
items = list((a, b, c))
items = {a, b, c}
135
Remove at most 1 item from list items, having the value x.
This will alter the original list or return a new list, depending on which is more idiomatic.
If there are several occurrences of x in items, remove only one of them. If x is absent, keep items unchanged.
items.remove(x)
136
Remove all occurrences of the value x from list items.
This will alter the original list or return a new list, depending on which is more idiomatic.
newlist = [item for item in items if item != x]
137
Set the boolean b to true if the string s contains only characters in the range '0'..'9', false otherwise.
b = s.isdigit()
Alternative implementation:
f = lambda x: x in digits
b = all(f(x) for x in s)
b = b and bool(len(s))
b = tonumber(s) ~= nil
138
Create a new temporary file on the filesystem.
file = tempfile.TemporaryFile()
file = io.tmpfile()
139
Create a new temporary folder on filesystem, for writing.
td = tempfile.TemporaryDirectory()
140
Delete from map m the entry having key k.

Explain what happens if k is not an existing key in m.
m.pop(k, None)
m[k]=nil
141
Iterate in sequence over the elements of the list items1 then items2. For each iteration print the element.
for x in items1 + items2:
    print(x)
Alternative implementation:
for x in chain(items1, items2): print(x)
142
Assign to string s the hexadecimal representation (base 16) of integer x.

E.g. 999 -> "3e7"
s = hex(x)
Alternative implementation:
s = format(x, 'x')
s = string.format("%x",x)
143
Iterate alternatively over the elements of the lists items1 and items2. For each iteration, print the element.

Explain what happens if items1 and items2 have different size.
for pair in zip(item1, item2): print(pair)
Alternative implementation:
for x in z(items1, items2): print(x)
144
Set boolean b to true if file at path fp exists on filesystem; false otherwise.

Beware that you should not do this and then in the next instruction assume the result is still valid, this is a race condition on any multitasking OS.
b = os.path.exists(fp)
Alternative implementation:
b = Path(fp).exists()
145
Print message msg, prepended by current date and time.

Explain what behavior is idiomatic: to stdout or stderr, and what the date format is.
logging.basicConfig(stream=sys.stdout, level=logging.DEBUG, format="%(asctime)-15s %(message)s")
logger = logging.getLogger('NAME OF LOGGER')

logger.info(msg)
146
Extract floating point value f from its string representation s
s = u'545,2222'
locale.setlocale(locale.LC_ALL, 'de')
f = locale.atof(s)
Alternative implementation:
f = float(s)
Alternative implementation:
f = float(s)
147
Create string t from string s, keeping only ASCII characters
t = re.sub('[^\u0000-\u007f]', '',  s)
Alternative implementation:
t = s.encode("ascii", "ignore").decode()
Alternative implementation:
f = lambda x: ord(x) < 0x80
t = ''.join(filter(f, list(s)))
148
Read a list of integer numbers from the standard input, until EOF.
list(map(int, input().split()))
Alternative implementation:
numbers = [int(x) for x in input().split()]
150
Remove the last character from the string p, if this character is a forward slash /
p = p.rstrip("/")
p = string.gsub(p,"/$","")
151
Remove last character from string p, if this character is the file path separator of current platform.

Note that this also transforms unix root path "/" into the empty string!
if p.endswith(os.sep):
    p = p[:-1]
if string.sub(p, -1, -1) == "/" then
	p=string.sub(p, 1, -2)
end
152
Create string s containing only the character c.
s = c
s = c
153
Create the string t as the concatenation of the string s and the integer i.
t = f"{s}{i}"
t = s .. i
154
Find color c, the average between colors c1, c2.

c, c1, c2 are strings of hex color codes: 7 chars, beginning with a number sign # .
Assume linear computations, ignore gamma corrections.
r1, g1, b1 = [int(c1[p:p+2], 16) for p in range(1,6,2)]
r2, g2, b2 = [int(c2[p:p+2], 16) for p in range(1,6,2)]
c = '#{:02x}{:02x}{:02x}'.format((r1+r2) // 2, (g1+g2) //2, (b1+b2)// 2)
Alternative implementation:
class RGB(numpy.ndarray):
  @classmethod
  def from_str(cls, rgbstr):
    return numpy.array([
      int(rgbstr[i:i+2], 16)
      for i in range(1, len(rgbstr), 2)
    ]).view(cls)
 
  def __str__(self):
    self = self.astype(numpy.uint8)
    return '#' + ''.join(format(n, 'x') for n in self)
 
c1 = RGB.from_str('#a1b1c1')
print(c1)
c2 = RGB.from_str('#1A1B1C')
print(c2)

print((c1 + c2) / 2)
Alternative implementation:
s = slice(1, 7)
x = bytes.fromhex(c1[s])
y = bytes.fromhex(c2[s])
f = lambda x: sum(x) // 2
r, g, b = map(f, zip(x, y))
c = (r << 16) + (g << 8) + b
c = f'#{c:06x}'
local c = "#"
for i=2,#c1,2 do
	local avg = (tonumber(c1:sub(i,i+1), 16) + tonumber(c2:sub(i,i+1), 16)) / 2
	c = c .. string.format("%02x", math.floor(avg))
end
155
Delete from filesystem the file having path filepath.
path = pathlib.Path(_filepath)
path.unlink()
Alternative implementation:
os.remove(filepath)
os.remove(filepath)
156
Assign to the string s the value of the integer i in 3 decimal digits. Pad with zeros if i < 100. Keep all digits if i1000.
s = format(i, '03d')
string.format("%03d", i)
157
Initialize a constant planet with string value "Earth".
PLANET = 'Earth'
PLANET = "Earth"
158
Create a new list y from randomly picking exactly k elements from list x.

It is assumed that x has at least k elements.
Each element must have same probability to be picked.
Each element from x must be picked at most once.
Explain if the original ordering is preserved or not.
y = random.sample(x, k)
159
Define a Trie data structure, where entries have an associated value.
(Not all nodes are entries)
class Trie:
   def __init__(self, prefix, value=None):
       self.prefix = prefix
       self.children = []
       self.value = value
local function New(base,new)
 return setmetatable(new,{__index=base})
end
local Trie={}
function Trie.New()
 return New(Trie,{
  children={},
  value=nil
 })
end
160
Execute f32() if platform is 32-bit, or f64() if platform is 64-bit.
This can be either a compile-time condition (depending on target) or a runtime detection.
if sys.maxsize > 2**32:
    f64()
else:
    f32()

161
Multiply all the elements of the list elements by a constant c
elements = [c * x for x in elements]
Alternative implementation:
f = lambda x: x * c
elements = list(map(f, elements))
local function map(t,fn)
 for i,v in ipairs(t) do
  t[i]=fn(v)
 end
 return t
end

local ret=map(elements,function(x) return x*c end)
162
execute bat if b is a program option and fox if f is a program option.
if 'b' in sys.argv[1:]: bat()
if 'f' in sys.argv[1:]: fox()
Alternative implementation:
options = {
	'b': bat
	'f': fox
}

for option, function in options:
	if option in sys.argv[1:]:
		function()
163
Print all the list elements, two by two, assuming list length is even.
for x in zip(list[::2], list[1::2]):
    print(x)
Alternative implementation:
def pairwise(iterable):
    "s -> (s0,s1), (s1,s2), (s2, s3), ..."
    a, b = tee(iterable)
    next(b, None)
    return zip(a, b)

for a, b in pairwise(list):
    print(a, b)
Alternative implementation:
for x in batched(a, 2): print(x)
Alternative implementation:
i = iter(a)
for x in zip_longest(i, i):
    print(x)
164
Open the URL s in the default browser.
Set the boolean b to indicate whether the operation was successful.
webbrowser.open(s)
165
Assign to the variable x the last element of the list items.
x = items[-1]
local x = items[#items]
166
Create the list ab containing all the elements of the list a, followed by all the elements of the list b.
ab = a + b
ab = {}

table.foreach(a, function(k, v) table.insert(ab, v) end)
table.foreach(b, function(k, v) table.insert(ab, v) end)
Alternative implementation:
ab = {}

table.move(a, 1, #a, 1, ab)
table.move(b, 1, #b, #ab + 1, ab)
167
Create the string t consisting of the string s with its prefix p removed (if s starts with p).
t = s[s.startswith(p) and len(p):]
Alternative implementation:
t = s.removeprefix(p)
local t = (s:sub(0, #p) == p) and s:sub(#p+1) or s
168
Create string t consisting of string s with its suffix w removed (if s ends with w).
t = s.removesuffix(w)
local t = s:gsub(w.."$", "")
169
Assign to the integer n the number of characters of the string s.
Make sure that multibyte characters are properly handled.
n can be different from the number of bytes of s.
n = len(s)
local n = utf8.len(s)
Alternative implementation:
local utf8={}
function utf8.bytes(str,index)
 local byte=string.byte(str,index)
 local ret
 if     byte==nil then ret=0
 elseif byte<128  then ret=1
 elseif byte<192  then ret=2
 elseif byte<224  then ret=3
 else                  ret=4
 end
 return ret
end
function utf8.len(str)
 local count=0
 local fini=#str+1
 local index=1
 while index~=fini do
  count=count+1
  index=index+utf8.bytes(str,index)
 end
 return count
end
local n=utf8.len(s)
170
Set n to the number of elements stored in mymap.

This is not always equal to the map capacity.
n = len(mymap)
local n=0
for _ in pairs(mymap) do n=n+1 end
171
Append the element x to the list s.
s.append(x)
s[#s + 1] = x
Alternative implementation:
table.insert(s, x)
172
Insert value v for key k in map m.
m[k] = v
173
Number will be formatted with a comma separator between every group of thousands.
f'{1000:,}'
Alternative implementation:
format(1000, ',')
Alternative implementation:
'{:,}'.format(1000)
174
Make a HTTP request with method POST to the URL u
data = parse.urlencode(<your data dict>).encode()
req =  request.Request(u, data=data, method="POST")
resp = request.urlopen(req)
175
From the array a of n bytes, build the equivalent hex string s of 2n digits.
Each byte (256 possible values) is encoded as two hexadecimal characters (16 possible values per digit).
s = a.hex()
for i,v in ipairs(a) do
 a[i]=string.format("%02x",v)
end
local s=table.concat(a)
176
From hex string s of 2n digits, build the equivalent array a of n bytes.
Each pair of hexadecimal characters (16 possible values per digit) is decoded into one byte (256 possible values).
a = bytearray.fromhex(s)
177
Construct a list L that contains all filenames that have the extension ".jpg" , ".jpeg" or ".png" in directory D and all its subdirectories.
extensions = [".jpg", ".jpeg", ".png"]
L = [f for f in os.listdir(D) if os.path.splitext(f)[1] in extensions]
Alternative implementation:
filtered_files = ["{}/{}".format(dirpath, filename) for dirpath, _, filenames in os.walk(D) for filename in filenames if re.match(r'^.*\.(?:jpg|jpeg|png)$', filename)]
Alternative implementation:
list(itertools.chain(*(glob.glob("*/**.%s" % ext) for ext in ["jpg", "jpeg", "png"])))
Alternative implementation:
extensions = [".jpg", ".jpeg", ".png"]
L = [f for f in glob.glob(os.path.join(D, "**/*"), recursive=True) if os.path.splitext(f)[1] in extensions]
178
Set boolean b to true if if the point with coordinates (x,y) is inside the rectangle with coordinates (x1,y1,x2,y2) , or to false otherwise.
Describe if the edges are considered to be inside the rectangle.
b = (x1 < x < x2) and (y1 < y < y2)
Alternative implementation:
class R:
    def __init__(self, x, y, w, h):
        self.x, self.y = x, y
        self.w, self.h = w, h
    def contains(self, x, y):
        t = self.x <= x <= (self.x + w)
        return t and self.y <= y <= (self.y + h)
w, h = x2 - x1, y2 - y1
b = R(x1, y1, w, h).contains(x, y)
179
Return the center c of the rectangle with coördinates(x1,y1,x2,y2)
center = ((x1+x2)/2, (y1+y2)/2)
Alternative implementation:
Point = namedtuple('Point', 'x y')
center = Point((x1+x2)/2, (y1+y2)/2)
Alternative implementation:
class R:
    def __init__(self, x, y, w, h):
        self.x, self.y = x, y
        self.w, self.h = w, h
    def center(self):
        return {
            'x': (self.x + self.w) / 2,
            'y': (self.y + self.h) / 2
        }
w, h = x2 - x1, y2 - y1
c = R(x1, y1, w, h).center()
180
Create the list x containing the contents of the directory d.

x may contain files and subfolders.
No recursive subfolder listing.
x = os.listdir(d)
182
Output the source of the current program. A quine is a computer program that takes no input and produces a copy of its own source code as its only output.

Reading the source file from disk is cheating.
s = 's = %r\nprint(s%%s)'
print(s%s)
x = [["x = [" .. "[" .. x .. "]" .. "]\nprint(" .. x)]]
print("x = [" .. "[" .. x .. "]" .. "]\nprint(" .. x)
183
Make a HTTP request with method PUT to the URL u
content_type = 'text/plain'
headers = {'Content-Type': content_type}
data = {}

r = requests.put(u, headers=headers, data=data)
status_code, content = r.status_code, r.content
184
Assign to variable t a string representing the day, month and year of the day after the current date.
t = str(date.today() + timedelta(days=1))
185
Schedule the execution of f(42) in 30 seconds.
timer = threading.Timer(30.0, f, args=(42,) ) 
timer.start() 
186
Exit a program cleanly indicating no error to OS
sys.exit(0)
os.exit(0)
187
Disjoint Sets hold elements that are partitioned into a number of disjoint (non-overlapping) sets.
class UnionFind:
    def __init__(self, size):
        self.rank = [0] * size
        self.p = [i for i in range(size)]

    def find_set(self, i):
        if self.p[i] == i:
            return i
        else:
            self.p[i] = self.find_set(self.p[i])
            return self.p[i]

    def is_same_set(self, i, j):
        return self.find_set(i) == self.find_set(j)

    def union_set(self, i, j):
        if not self.is_same_set(i, j):
            x, y = self.find_set(i), self.find_set(j)
 
188
Perform matrix multiplication of a real matrix a with nx rows and ny columns, a real matrix b with ny rows and nz columns and assign the value to a real matrix c with nx rows and nz columns.
c = a @ b
Alternative implementation:
c = np.matmul(a, b)
189
Produce a new list y containing the result of the function T applied to all elements e of the list x that match the predicate P.
y = [T(e) for e in x if P(e)]
Alternative implementation:
y = list(map(T, filter(P, x)))
190
Declare an external C function with the prototype

void foo(double *a, int n);

and call it, passing an array (or a list) of size 10 to a and 10 to n.

Use only standard features of your language.
a = (c_int * 10)(*range(10))
n = 10
libc = cdll.LoadLibrary('/path/to/c_library')
libc.foo(c_void_p(a), c_int(n))
191
Given a one-dimensional array a, check if any value is larger than x, and execute the procedure f if that is the case
if any(v > x for v in a):
    f()
192
Declare a real variable a with at least 20 digits; if the type does not exist, issue an error at compile time.
a = decimal.Decimal('1234567890.123456789012345')
193
Declare two two-dimensional arrays a and b of dimension n*m and m*n, respectively. Assign to b the transpose of a (i.e. the value with index interchange).
a = np.array([[1,2], [3,4], [5,6]])
b = a.T
Alternative implementation:
a = [[1,2], [3,4], [5,6]]
b = list(map(list, zip(*a)))
Alternative implementation:
b = list(zip(*a))
local a = {}

for x = 1, n do
  local t = {}
  for y = 1, m do
    t[y] = {x, y}
  end
  a[x] = t
end
  
local b = {}

for y = 1, m do
  local t = {}
  for x = 1, n do
    t[x] = a[x][y]
  end
  b[y] = t
end
194
Given an array a, set b to an array which has the values of a along its second dimension shifted by n. Elements shifted out should come back at the other end.
b = np.roll(a, m, axis=1)
195
Pass an array a of real numbers to the procedure (resp. function) foo. Output the size of the array, and the sum of all its elements when each element is multiplied with the array indices i and j (assuming they start from one).
def foo(a):
    print(len(a))
    print(sum(
        x*(i+1) + y*(i+1)*2 for i, (x, y) in enumerate(a)
    ))
Alternative implementation:
def foo(a: list[list[float]]):
    print(len(a))
    z = 0
    for i, x in enumerate(a):
        for j, y in enumerate(x):
            z = z + (y * (i + 1))
            z = z + (y * (j + 1))
    print(z)
Alternative implementation:
def foo(a):
    z = 0
    for i, m in enumerate(a, 1):
        for j, n in enumerate(m, 1):
            z = z + (n * i * j)
    print(len(a), z)
196
Given an integer array a of size n, pass the first, third, fifth and seventh, ... up to the m th element to a routine foo which sets all these elements to 42.
def foo(data, r):
    for i in r: 
        data[i] = 42

foo(a, range(0, m+1, 2))
Alternative implementation:
def foo(s: slice):
    global a
    m = (s.stop - 1) - s.start
    a[s] = [42] * ((m // s.step) + 1)
foo(slice(0, m + 1, 2))
197
Retrieve the contents of file at path into a list of strings lines, in which each element is a line of the file.
with open(path) as f:
    lines = f.readlines()
198
Abort program execution with error condition x (where x is an integer value)
sys.exit(x)
os.exit(x)
199
Truncate a file F at the given file position.
F.truncate(F.tell())
200
Compute the hypotenuse h of the triangle where the sides adjacent to the square angle have lengths x and y.
h = math.hypot(x, y)
local h = math.sqrt(x^2 + y^2)
Alternative implementation:
local h=(x^2+y^2)^0.5
201
Calculate n, the Euclidean norm of data (an array or list of floating point values).
np.linalg.norm(adata2[:, 0:3] - adata1[ipc1, 0:3], axis=1)
Alternative implementation:
n = np.linalg.norm(data)
202
Calculate the sum of squares s of data, an array of floating point values.
s = sum(i**2 for i in data)
Alternative implementation:
f = lambda x: x * x
s = sum(map(f, data))
203
Calculate the mean m and the standard deviation s of the list of floating point values data.
m = statistics.mean(data)
sd = statistics.stdev(data)
204
Given a real number a, print the fractional part and the exponent of the internal representation of that number. For 3.14, this should print (approximately)

0.785 2
print(math.frexp(a))
local function frexp(a)
	return math.frexp(a)
end
205
Read an environment variable with the name "FOO" and assign it to the string variable foo. If it does not exist or if the system does not support environment variables, assign a value of "none".
try:
    foo = os.environ['FOO']
except KeyError:
    foo = "none"
Alternative implementation:
foo = getenv('FOO', 'none')
Alternative implementation:
foo = os.environ.get('FOO', 'none')
foo = os.getenv("FOO") or "none"
206
Execute different procedures foo, bar, baz and barfl if the string str contains the name of the respective procedure. Do it in a way natural to the language.
switch = {'foo': foo, 
	'bar': bar, 
	'baz': baz, 
	'barfl': barfl
	}

switch_funct = switch.get(string)
if switch_funct : switch_funct()
Alternative implementation:
match str:
    case 'foo': foo()
    case 'bar': bar()
    case 'baz': baz()
    case 'barfl': barfl()
local procedures={
 foo=function() end,
 bar=function() end,
 baz=function() end,
 barfl=function() end,
}
local function process(str)
 local procedure=procedures[str]
 if procedure~=nil then
  procedure()
 end
end
process(str)
207
Allocate a list a containing n elements (n assumed to be too large for a stack) that is automatically deallocated when the program exits the scope it is declared in.
def func():
    a = [0] * n
    # local variable automatically deallocated at end of function
    return
208
Given the arrays a,b,c,d of equal length and the scalar e, calculate a = e*(a+b*c+cos(d)).
Store the results in a.
for i in xrange(len(a)):
	a[i] = e*(a[i] + b[i] + c[i] + math.cos(a[i]))
Alternative implementation:
a = [e*(a[i] + b[i] + c[i] + math.cos(d[i])) for i in range(len(a))]
Alternative implementation:
def f(a, b, c, d):
    return e * (a + b * c + cos(d))
a = sum(map(f, a, b, c, d))
209
Declare a type t which contains a string s and an integer array n with variable size, and allocate a variable v of type t. Allocate v.s and v.n and set them to the values "Hello, world!" for s and [1,4,9,16,25], respectively. Deallocate v, automatically deallocating v.s and v.n (no memory leaks).
class T:
    def __init__(self, s, n):
        self.s = s
        self.n = n
        return

v = T('hello world', [1, 4,  9, 16, 25])
del v
210
Assign, at runtime, the compiler version and the options the program was compiled with to variables version and options, respectively, and print them. For interpreted languages, substitute the version of the interpreter.

Example output:

GCC version 10.0.0 20190914 (experimental)
-mtune=generic -march=x86-64
version = sys.version
options = sys.flags
print(_VERSION)
211
Create the folder at path on the filesystem
os.mkdir(path)
212
Set the boolean b to true if path exists on the filesystem and is a directory; false otherwise.
b = os.path.isdir(path)
213
Compare four strings in pair-wise variations. The string comparison can be implemented with an equality test or a containment test, must be case-insensitive and must apply Unicode casefolding.
strings = ['ᾲ στο διάολο', 
           'ὰι στο διάολο', 
           'Ὰͅ ΣΤΟ ΔΙΆΟΛΟ', 
           'ᾺΙ ΣΤΟ ΔΙΆΟΛΟ']

for a, b in itertools.combinations(strings, 2):
    print(a, b, a.casefold() == b.casefold())
214
Append extra character c at the end of string s to make sure its length is at least m.
The length is the number of characters, not the number of bytes.
s = s.ljust(m, c)
215
Prepend extra character c at the beginning of string s to make sure its length is at least m.
The length is the number of characters, not the number of bytes.
s = s.rjust(m, c)
216
Add the extra character c at the beginning and ending of string s to make sure its length is at least m.
After the padding the original content of s should be at the center of the result.
The length is the number of characters, not the number of bytes.

E.g. with s="abcd", m=10 and c="X" the result should be "XXXabcdXXX".
s = s.center(m, c)
217
Create a zip-file with filename name and add the files listed in list to that zip-file.
with zipfile.ZipFile(name, 'w', zipfile.ZIP_DEFLATED) as zip:
    for file in list_:
        zip.write(file)
218
Create the list c containing all unique elements that are contained in both lists a and b.
c should not contain any duplicates, even if a and b do.
The order of c doesn't matter.
c = list(set(a) & set(b))
Alternative implementation:
c = list(set(a).intersection(b))
219
Create the string t from the value of string s with each sequence of spaces replaced by a single space.

Explain if only the space characters will be replaced, or the other whitespaces as well: tabs, newlines.
t = re.sub(' +', ' ', s)
Alternative implementation:
t: str = " ".join(s.split())
Alternative implementation:
t = ' '.join(split(' {2,}', s))
Alternative implementation:
t = ' '.join(split(r'\s{2,}', s))
local t = s:gsub("%s+", " ")
220
Create t consisting of 3 values having different types.

Explain if the elements of t are strongly typed or not.
t = (2.5, "hello", -1)
Alternative implementation:
t = tuple('abc', 123, true)
221
Create string t from string s, keeping only digit characters 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
t = re.sub(r"\D", "", s)
Alternative implementation:
f = lambda x: x in digits
t = ''.join(filter(f, s))
222
Set i to the first index in list items at which the element x can be found, or -1 if items does not contain x.
i = items.index(x) if x in items else -1
223
Loop through list items checking a condition. Do something else if no matches are found.

A typical use case is looping through a series of containers looking for one that matches a condition. If found, an item is inserted; otherwise, a new container is created.

These are mostly used as an inner nested loop, and in a location where refactoring inner logic into a separate function reduces clarity.
for item in items:
    if item == 'baz':
        print('found it')
        break
else:
    print('never found it')
local function list_cond(t,cond)
 for _,v in ipairs(t) do
  if cond(v)==true then return true end
 end
 return false
end
if list_cond(items,function(x) return x==0 end) then
 print("did find 0")
else
 print("didn't find 0")
end
224
Insert the element x at the beginning of the list items.
items = [x] + items
Alternative implementation:
items.insert(0, x)
table.insert(items, 1, x)
225
Declare an optional integer argument x to procedure f, printing out "Present" and its value if it is present, "Not present" otherwise
def f(x=None):
    if x is None:
        print("Not present")
    else:
        print("Present", x)
function f( x )
	if x then
		print("Present", x)
	else
		print("Not present")
	end
end
226
Remove the last element from the list items.
items.pop()
227
Create the new list y containing the same elements as the list x.

Subsequent modifications of y must not affect x (except for the contents referenced by the elements themselves if they contain pointers).
y = x[:]
Alternative implementation:
y = x.copy()
local function deepcopy(input)
 local t=type(input)
 if t~="table" then
  return input
 end
 local copy={}
 for k,v in pairs(input) do
  k=deepcopy(k)
  v=deepcopy(v)
  copy[k]=v
 end
 return copy
end
local y=deepcopy(x)
228
Copy the file at path src to dst.
shutil.copy(src, dst)
231
Set b to true if the byte sequence s consists entirely of valid UTF-8 character code points, false otherwise.
try:
    s.decode('utf8')
    b = True
except UnicodeError:
    b = False

232
Print "verbose is true" if the flag -v was passed to the program command line, "verbose is false" otherwise.
parser = argparse.ArgumentParser()
parser.add_argument('-v', action='store_true', dest='verbose')
args = parser.parse_args()
print('verbose is', args.verbose)
233
Print the value of the flag -country passed to the program command line, or the default value "Canada" if no such flag was passed.
parser = argparse.ArgumentParser()
parser.add_argument('-country', default='Canada', dest='country')
args = parser.parse_args()
print('country is', args.country)
234
Assign to the string s the standard base64 encoding of the byte array data, as specified by RFC 4648.
b = base64.b64encode(data)
s = b.decode()
235
Assign to byte array data the bytes represented by the base64 string s, as specified by RFC 4648.
data = base64.decode(s)
236
Initialize a quotient q = a/b of arbitrary precision. a and b are large integers.
q = fractions.Fraction(a, b)
237
Assign to c the result of (a xor b)
c = a ^ b
238
Write in a new byte array c the xor result of byte arrays a and b.

a and b have the same size.
c = bytes([aa ^ bb for aa, bb in zip(a, b)])
Alternative implementation:
c = list(map(xor, a, b))
local c = {}
for i=1,#a do
	c[i] = string.char(string.byte(a, i) ~ string.byte(b, i))
end
c = table.concat(c)
239
Assign to string x the first word of string s consisting of exactly 3 digits, or the empty string if no such match exists.

A word containing more digits, or 3 digits as a substring fragment, must not match.
m = re.search(r'\b\d\d\d\b', s)
x = m.group(0) if m else ''
240
Lists a and b have the same length. Apply the same permutation to a and b to have them sorted based on the values of a.
temp = list(zip(a, b))
temp.sort(key=operator.itemgetter(0))
a, b = zip(*work)
242
Call a function f on each element e of a set x.
for e in x:
    f(e)
Alternative implementation:
list(map(lambda e: f(e), x))
Alternative implementation:
for e in x: f(e)
243
Print the contents of the list or array a on the standard output.
print(a)
print(table.concat(a,", "))
244
Print the contents of the map m to the standard output: keys and values.
print(m)
245
Print the value of object x having custom type T, for log or debug.
print(x)
246
Set c to the number of distinct elements in the list items.
c = len(set(items))
local c=#items
247
Remove all the elements from list x that don't satisfy the predicate p, without allocating a new list.
Keep all the elements that do satisfy p.

For languages that don't have mutable lists, refer to idiom #57 instead.
del_count = 0
for i in range(len(x)):
    if not p(x[i - del_count]):
        del x[i - del_count]
        del_count += 1
Alternative implementation:
x = list(filter(p, x))
248
Construct the "double precision" (64-bit) floating point number d from the mantissa m, the exponent e and the sign flag s (true means the sign is negative).
sign = -1 if s else 1
d = math.ldexp(sign*m,e)
249
Define variables a, b and c in a concise way.
Explain if they need to have the same type.
a, b, c = 42, 'hello', 5.0
Alternative implementation:
a, b, c = 'xyz'
Alternative implementation:
a, b, *c = '1111011'
Alternative implementation:
*a, b, c = '1111011'
Alternative implementation:
a, b, c = Decimal(1.23).as_tuple()
250
Choose a value x from map m.
m must not be empty. Ignore the keys.
x = random.choice(list(m.values()))
251
Extract integer value i from its binary string representation s (in radix 2)
E.g. "1101" -> 13
i = int(s, 2)
252
Assign to the variable x the string value "a" if calling the function condition returns true, or the value "b" otherwise.
x = "a" if condition() else "b"
253
Print the stack frames of the current execution thread of the program.
for frame in inspect.stack():
    print(frame)
254
Replace all exact occurrences of "foo" with "bar" in the string list x
for i, v in enumerate(x):
  if v == "foo":
    x[i] = "bar"
Alternative implementation:
x = ["bar" if v=="foo" else v for v in x]
Alternative implementation:
f = lambda x: 'bar' if x == 'foo' else x
x = list(map(f, x))
255
Print the values of the set x to the standard output.
The order of the elements is irrelevant and is not required to remain the same next time.
print(x)
256
Print the numbers 5, 4, ..., 0 (included), one line per number.
for i in range(5, -1, -1):
    print(i)
Alternative implementation:
a = reversed(range(0, 5 + 1))
for x in a: print(x)
for i=5, 0, -1 do
	print(i)
end
257
Print each index i and value x from the list items, from the last down to the first.
for i in range(len(items)-1, -1, -1):
    print(i, items[i])
Alternative implementation:
for i, x in enumerate(reversed(items)):
  print(f'{i} {x}')
Alternative implementation:
a = list(enumerate(items))
for e in reversed(a): print(e)
258
Convert the string values from list a into a list of integers b.
b = [int(elem) for elem in a]
Alternative implementation:
b = list(map(int, a))
259
Build the list parts consisting of substrings of the input string s, separated by any of the characters ',' (comma), '-' (dash), '_' (underscore).
parts = re.split('[,_\-]', s)
Alternative implementation:
z = escape(',-_')
parts = split(f'[{z}]', s)
260
Declare a new list items of string elements, containing zero elements
items = []
261
Assign to the string x the value of fields (hours, minutes, seconds) of the date d, in format HH:MM:SS.
d = datetime.datetime.now()
x = d.strftime('%H:%M:%S')
262
Assign to t the number of trailing 0 bits in the binary representation of the integer n.

E.g. for n=112, n is 1110000 in base 2 ⇒ t=4
t = bin(n)[::-1].find('1')
Alternative implementation:
b = len(s := format(n, 'b'))
t = b - len(s.rstrip('0'))
263
Write two functions log2d and log2u, which calculate the binary logarithm of their argument n rounded down and up, respectively. n is assumed to be positive. Print the result of these functions for numbers from 1 to 12.
def log2d(n):
    return math.floor(math.log2(n))

def log2u(n):
    return math.ceil(math.log2(n))

for n in range(1, 13):
    print(n, log2d(n), log2u(n))
Alternative implementation:
log2d = lambda x: floor(log2(x))
log2u = lambda x: ceil(log2(x))
for i in range(1, 13):
    print(i, log2d(i), log2u(i))
264
Pass a two-dimensional integer array a to a procedure foo and print the size of the array in each dimension. Do not pass the bounds manually. Call the procedure with a two-dimensional array.
def foo(a):
    print(len(a), len(a[0]))
    return


a = [[1,2,3], [4,5,6]]
foo(a)
265
Calculate the parity p of the integer variable i : 0 if it contains an even number of bits set, 1 if it contains an odd number of bits set.
p = bin(i).count('1') % 2
266
Assign to the string s the value of the string v repeated n times, and write it out.

E.g. v="abc", n=5 ⇒ s="abcabcabcabcabc"
s = v * n
s = string.rep(v, n)
267
Declare an argument x to a procedure foo that can be of any type. If the type of the argument is a string, print it, otherwise print "Nothing."

Test by passing "Hello, world!" and 42 to the procedure.
def foo(x):
    if isinstance(x, str):
        print(x)
    else:
        print('Nothing.')
    return

foo('Hello, world!')
foo(42)
268
Define a type vector containing three floating point numbers x, y, and z. Write a user-defined operator x that calculates the cross product of two vectors a and b.
class Vector:
    def __init__(self, x, y, z):
        self.x = x
        self.y = y
        self.z = z
        return

    def __mul__(self, other):
        return Vector(self.y * other.z - self.z * other.y,
                      self.z * other.x - self.x * other.z,
                      self.x * other.y - self.y * other.x)

result = a * b
Alternative implementation:
class V:
    def __init__(self, x, y, z):
        self.a = x, y, z
    def __mul__(self, b):
        a = self.a
        return {
            'x': a[1] * b[2] - a[2] * b[1],
            'y': a[2] * b[0] - a[0] * b[2],
            'z': a[0] * b[1] - a[1] * b[0]
        }
a, b = V(.1, .2, .3), V(.4, .5, .6)
vector = a * b
local Vector={x=0,y=0,z=0}
---@type metatable
local mt={
 __index=Vector,
}
function mt.__add(a,b)
 return Vector.new(
  a.x+b.x,
  a.y+b.y,
  a.z+b.z
 )
end
function Vector.new(x,y,z)
 return setmetatable({x=x,y=y,z=z},mt)
end
269
Given the enumerated type t with 3 possible values: bike, car, horse.
Set the enum value e to one of the allowed values of t.
Set the string s to hold the string representation of e (so, not the ordinal value).
Print s.
e = T.horse
s = e.name
print(s)
270
Given a floating point number r1 classify it as follows:
If it is a signaling NaN, print "This is a signaling NaN."
If it is a quiet NaN, print "This s a quiet NaN."
If it is not a NaN, print "This is a number."
if math.isnan(r1):
    print('This is a quiet NaN.')
else:
    print('This is a number.')
Alternative implementation:
d = Decimal(r1)
if d.is_snan(): print('This is a signaling NaN.')
if d.is_qnan(): print('This s a quiet NaN.')
if not d.is_nan(): print('This is a number.')
271
If a variable x passed to procedure tst is of type foo, print "Same type." If it is of a type that extends foo, print "Extends type." If it is neither, print "Not related."
def tst(x):
    if type(x) == foo:
        print("Same type.")
    elif isinstance(x, foo):
        print("Extends type.")
    else:
        print("Not related.")
272
Fizz buzz is a children's counting game, and a trivial programming task used to affirm that a programmer knows the basics of a language: loops, conditions and I/O.

The typical fizz buzz game is to count from 1 to 100, saying each number in turn. When the number is divisible by 3, instead say "Fizz". When the number is divisible by 5, instead say "Buzz". When the number is divisible by both 3 and 5, say "FizzBuzz"
for i in range(1,101):
    if i % 15 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)
Alternative implementation:
n=1
while(n<=100):
    out=""
    if(n%3==0):
        out=out+"Fizz"
    if(n%5==0):
        out=out+"Buzz"
    if(out==""):
        out=out+str(n)
    print(out)
    n=n+1
Alternative implementation:
for i in range(100, 1):
    if i % 5 == 0 and not i % 3 == 0:
        print(i, "Buzz");
    if i % 3 == 0 and not i % 5 == 0:
        print(i, "Fizz");
    if i % 3 == 0 and i % 5 == 0:
        print(i, "FizzBuzz");
Alternative implementation:
for i in range(1, 100+1):
    out = ""
    if i % 3 == 0:
        out += "Fizz"
    if i % 5 == 0:
        out += "Buzz"
    print(out or i)
n=1
while(n<=100) do
    out=""
    if(n%3==0) then
        out=out .. "Fizz"
    end
    if(n%5==0) then
        out=out .. "Buzz"
    end
    if(out=="") then
        out=out .. tostring(n)
    end
    print(out)
    n=n+1
end
Alternative implementation:
for n=1,100 do
 print(
  n%3==0
  and (n%5==0 and "FizzBuzz" or "Fizz")
  or (n%5==0 and "Buzz")
  or tostring(n)
 )
end
273
Set the boolean b to true if the directory at filepath p is empty (i.e. doesn't contain any other files and directories)
b = os.listdir(p) == []
274
Create the string t from the string s, removing all the spaces, newlines, tabulations, etc.
t = re.sub('\\s', '', s)
Alternative implementation:
t = ''.join(s.split())
Alternative implementation:
f = lambda x: x not in whitespace
t = ''.join(filter(f, list(s)))
275
From the string s consisting of 8n binary digit characters ('0' or '1'), build the equivalent array a of n bytes.
Each chunk of 8 binary digits (2 possible values per digit) is decoded into one byte (256 possible values).
n = (len(s) - 1) // 8 + 1
a = bytearray(n)
for i in range(n):
    b = int(s[i * 8:(i + 1) * 8], 2)
    a[i] = b
Alternative implementation:
f = lambda x: int(s[x:x + 8], 2)
a = list(map(f, range(0, len(s), 8)))
Alternative implementation:
f = lambda x: int(''.join(x), 2)
a = list(map(f, batched(s, 8)))
Alternative implementation:
p = re.compile('.{8}').findall(s)
f = lambda x: int(x, 2)
a = list(map(f, p))
276
Insert an element e into the set x.
x.add(e)
x[e] = true
277
Remove the element e from the set x.

Explains what happens if e was already absent from x.
x.remove(e)
278
Read one line into the string line.

Explain what happens if EOF is reached.
line = sys.stdin.readline()
279
Read all the lines (until EOF) into the list of strings lines.
lines = sys.stdin.readlines()
280
Remove all the elements from the map m that don't satisfy the predicate p.
Keep all the elements that do satisfy p.

Explain if the filtering happens in-place, i.e. if m is reused or if a new map is created.
m = {k:v for k, v in m.items() if p(v)}
Alternative implementation:
for k in list(m):
    if p(m[k]): m.pop(k)
Alternative implementation:
m = dict(filter(p, m.items()))
281
You have a Point with integer coordinates x and y. Create a map m with key type Point (or equivalent) and value type string. Insert "Hello" at position (42, 5).
m = dict()
p = Point(x=42, y=5)
m[p] = 'Hello'
Alternative implementation:
Point = namedtuple('Point', 'x y')

p = Point(42, 5)

m = {p: "Hello"}
Alternative implementation:
m = {Point(42, 5): 'Hello'}
282
Declare a type Foo, and create a new map with Foo as key type.

Mention the conditions on Foo required to make it a possible map key type.
class Foo:
    def __init__(self, x, y):
        self.x = x
        self.y = y
    def __hash__(self):
        return hash((Foo, self.x, self.y))
    def __eq__(self, other):
        return (self.x, self.y) == (other.x, other.y)

foo = Foo(1, 2)
m = {foo: 'hello'}
local map={[Foo]=true}
283
Build the list parts consisting of substrings of input string s, separated by the string sep.
parts = s.split(sep)
local function split(s,sep)
 local parts={}
 for sub in string.gmatch(s,"[^"..sep.."]+") do
  table.insert(parts,sub)
 end
 return parts
end
284
Create a new list a (or array, or slice) of size n, where all elements are integers initialized with the value 0.
a = [0] * n
Alternative implementation:
a = list(repeat(0, n))
local function new_zeroed_list(n)
 local ret={}
 for i=1,n do
  ret[i]=0
 end
 return ret
end
local zeroed_list=new_zeroed_list(n)
285
Given two floating point variables a and b, set a to a to a quiet NaN and b to a signalling NaN. Use standard features of the language only, without invoking undefined behavior.
a = float('nan')
local a = 0/0
286
Print a line "Char i is c" for each character c of the string s, where i is the character index of c in s (not the byte index).

Make sure that multi-byte characters are properly handled, and count for a single character.
for i, c in enumerate(s):
    print(f'Char {i} is {c}')
Alternative implementation:
f = lambda i, c: f'Char {i} is {c}'
for e in enumerate(s): print(f(*e))
287
Assign to n the number of bytes in the string s.

This can be different from the number of characters. If n includes more bytes than the characters per se (trailing zero, length field, etc.) then explain it. One byte is 8 bits.
n = len(s.encode('utf8'))
288
Set the boolean b to true if the set x contains the element e, false otherwise.
b = e in x
289
Create the string s by concatenating the strings a and b.
s = a + b
Alternative implementation:
s = f'{a}{b}'
local s = a..b
290
Sort the part of the list items from index i (included) to index j (excluded), in place, using the comparator c.

Elements before i and after j must remain unchanged.
items[i:j] = sorted(items[i:j], key=functools.cmp_to_key(c))
Alternative implementation:
items[i:j] = sorted(items[i:j], key=c)
291
Delete all the elements from index i (included) to index j (excluded) from the list items.
items[i:j] = []
Alternative implementation:
del items[i:j]
local function erase(t,i,j)
 for i=1,j-1 do
  t[i]=nil
 end
end
erase(items,i,j)
292
Write "Hello World and 你好" to standard output in UTF-8.
print('Hello World and \u4f60\u597d')
Alternative implementation:
print('Hello World and 你好')
293
Create a new stack s, push an element x, then pop the element into the variable y.
s = []
s.append(x)
y = s.pop()
294
Given an array a containing the three values 1, 12, 42, print out
"1, 12, 42" with a comma and a space after each integer except the last one.
a = [1, 12, 42]
print(*a, sep=', ')
Alternative implementation:
print(a[0], end='')
for i in range(1, len(a)):
    print(',', a[i], end='')
Alternative implementation:
print(', '.join(map(str, a)))
Alternative implementation:
f = lambda x, y: f'{x}, {y}'
print(reduce(f, a))
295
Given the enumerated type T, create a function TryStrToEnum that takes a string s as input and converts it into an enum value of type T.

Explain whether the conversion is case sensitive or not.
Explain what happens if the conversion fails.
t = T[s]
296
Assign to x2 the value of string x with the last occurrence of y replaced by z.
If y is not contained in x, then x2 has the same value as x.
x2 = z.join(x.rsplit(y, 1))
297
Sort the string list data in a case-insensitive manner.

The sorting must not destroy the original casing of the strings.
data.sort(key=str.lower)
298
Create the map y by cloning the map x.

y is a shallow copy, not a deep copy.
y = x.copy()
299
Write a line of comments.

This line will not be compiled or executed.
# This is a comment
-- This is a comment
301
Compute the Fibonacci sequence of n numbers using recursion.

Note that naive recursion is extremely inefficient for this task.
def fib(n):
    if n < 0:
        raise ValueError
    if n < 2:
        return n
    return fib(n - 2) + fib(n - 1)
        
302
Given the integer x = 8, assign to the string s the value "Our sun has 8 planets", where the number 8 was evaluated from x.
s = f'Our sun has {x} planets'
Alternative implementation:
s = 'Our sun has {} planets'.format(x)
Alternative implementation:
s = 'Our sun has %s planets' % x
local str=string.format("Our sun has %d planets",x)
303
Declare an array a of integers with six elements, where the first index is 42 and consecutive elements have the indices 43, 44, 45, 46, 47.
a = array.array("i", range(42,48))
304
Create the array of bytes data by encoding the string s in UTF-8.
data = s.encode('utf8')
305
Compute and print a^b, and a^n, where a and b are floating point numbers and n is an integer.
print(a ** b, a ** n)
307
Create a function that XOR encrypts/decrypts a string
def xor(data, key):
	return ''.join(chr(ord(x)^ord(y)) for x,y in zip(data, cycle(key)))
308
Create the string representation s of the integer value n in base b.

18 in base 3 -> "200"
26 in base 5 -> "101"
121 in base 12 -> "a1"

def int_to_base_str(n, b):
    digits = '0123456789abcdefghijklmnopqrstuvwxyz'
    s = ''
    if n == 0: return '0'
    while n:
        n, remainder = divmod(n, b)
        s = digits[remainder] + s
    return s
Alternative implementation:
s = numpy.base_repr(n, b)
309
Create the new 2-dimensional array y containing a copy of the elements of the 2-dimensional array x.

x and y must not share memory. Subsequent modifications of y must not affect x.
y = copy.deepcopy(x)
310
Fill the byte array a with randomly generated bytes.
a[:] = random.randbytes(len(a))
Alternative implementation:
a = random.randbytes(N)
311
Create the new object y by cloning the all the contents of x, recursively.
y = copy.deepcopy(x)
312
Set b to true if the lists p and q have the same size and the same elements, false otherwise.
b = p == q
313
Set b to true if the maps m and n have the same key/value entries, false otherwise.
b = m == n
314
Set all the elements in the array x to the same value v
x[:] = [v] * len(x)
315
Given any function f, create an object or function m that stores the results of f, and calls f only on inputs for which the result is not stored yet.
@functools.lru_cache
def m(*args):
    return f(*args)

316
Determine the number c of elements in the list x that satisfy the predicate p.
c = sum(p(v) for v in x)
317
Create a string s of n characters having uniform random values out of the 62 alphanumeric values A-Z, a-z, 0-9
alphanum = string.ascii_letters + string.digits
s = ''.join(random.choices(alphanum, k=n))
Alternative implementation:
a = list(s.ascii_letters + s.digits)
r.shuffle(a)
s = ''.join(a[:n])
318
Assign to the integer x a random number between 0 and 17 (inclusive), from a crypto secure random number generator.
x = secrets.choice(range(0, 18))
Alternative implementation:
x = secrets.randbelow(18)
319
Write a function g that behaves like an iterator.
Explain if it can be used directly in a for loop.
def g():
    for i in range(6):
        yield i
320
Set b to true if the string s is empty, false otherwise
b = s == ''
Alternative implementation:
b = not s
321
Assign to c the value of the i-th character of the string s.

Make sure to properly handle multi-byte characters. i is the character index, which may not be equal to the byte index.
c = s[i]
322
old, x = x, new
323
Make an HTTP request with method GET to the URL u, with the request header "accept-encoding: gzip", then store the body of the response in the buffer data.
response = requests.get(u, headers={'accept-encoding': 'gzip'})
data = response.content[:]
324
Set the string c to the (first) value of the header "cache-control" of the HTTP response res.
c = res.headers['cache-control']
325
Create a new queue q, then enqueue two elements x and y, then dequeue an element into the variable z.
q = queue.Queue()
q.put(x)
q.put(y)
z = q.get()
326
Assign to t the number of milliseconds elapsed since 00:00:00 UTC on 1 January 1970.
t = time.time() * 1000
327
Assign to t the value of the string s, with all letters mapped to their lower case.
t = s.lower()
local t = string.lower(s)
328
Assign to t the value of the string s, with all letters mapped to their upper case.
t = s.upper()
local t = string.upper(s)
329
Assign to v the value stored in the map m for the key k.

Explain what happens if there is no entry for k in m.
v = m[k]
Alternative implementation:
v = m.get(k, "default value")
Alternative implementation:
v = m.get(k)
local v=m[k]
330
Create the list a containing all the values of the map m.

Ignore the keys of m. The order of a doesn't matter. a may contain duplicate values.
a = list(m.values())
331
Remove all entries from the map m.

Explain if other references to the same map now see an empty map as well.
m.clear()
332
Create the list k containing all the keys of the map m
k = m.keys()
Alternative implementation:
k = [*m.keys()]
Alternative implementation:
k = list(m.keys())
333
Print the object x in human-friendly JSON format, with newlines and indentation.
print(json.dumps(x, indent=4))
334
Create the new map c containing all of the (key, value) entries of the two maps a and b.

Explain what happens for keys existing in both a and b.
c = {**a, **b}
Alternative implementation:
c = a | b
335
Create the map m containing all the elements e of the list a, using as key the field e.id.
m = {e.id:e for e in a}
Alternative implementation:
f = lambda x: (x.id, x)
m = dict(map(f, a))
local m={}
for _,e in ipairs(a) do
 m[e.id]=e
end
336
Compute x = b

b raised to the power of n is equal to the product of n terms b × b × ... × b
x = b ** n
337
Extract the integer value i from its string representation s, in radix b
i = int(s, b)
338
Create a new bidirectional map bm and insert the pair (42, "forty-two")
bm = bidict.bidict({42: 'forty-two'})
339
Set all the elements of the byte array a to zero
a = numpy.ones((n,), numpy.uint8)
a.fill(0)
340
Assign to c the value of the last character of the string s.

Explain the type of c, and what happens if s is empty.

Make sure to properly handle multi-bytes characters.
c = s[-1]
341
Set i to the position of the last occurrence of the string y inside the string x, if exists.

Specify if i should be regarded as a character index or as a byte index.

Explain the behavior when y is not contained in x.
i = x.rfind(y)
342
Determine if the current year is a leap year.
if calendar.isleap(datetime.date.today().year):
    print('This year is a leap year.')
Alternative implementation:
y = date.today().year
b = not y % 4 and bool(y % 100 or not y % 400)
343
Rename the file at path1 into path2
os.rename(path1, path2)
344
Assign to ext the fragment of the string f after the last dot character, or the empty string if f does not contain a dot.

E.g. "photo.jpg" -> "jpg"

ext must not contain the dot character.
ext = os.path.splitext(f)[1][1:]
345
Create the integer value i initialized from its string representation s (in radix 10)

Use an integer type that can hold huge values. Explain what happens if s cannot be parsed.
i = int(s)
346
Create the list y from the list x repeated n times
94102
347
Copy the directory path1 to path2, with all its contents
shutil.copytree(path1, path2)
348
Parse a number, a, into a mathematical fraction, f.

For example, 0.5 is `1/2`, and 3.125 is `3 1/8`.

https://en.wikipedia.org/wiki/Fraction
s = str(a).split('.')
i, n = map(int, s)
d = 10 ** len(str(n))
v = gcd(n, d) or 1
n, d = n // v, d // v
if not n: f = str(i)
elif i: f = f'{i} {n}/{d}'
else: f = f'{n}/{d}'
Alternative implementation:
f = Fraction(a)
349
Parse a value, f, into a decimal number, a.

For example, `1/2` is 0.5, and `3 1/8` is 3.125.

https://en.wikipedia.org/wiki/Fraction
z = 0
if (i := f.find(' ')) != -1:
    z = int(f[:i])
    f = f[i + 1:].lstrip()
n, d = map(int, f.split('/'))
a = z + (n / d)
Alternative implementation:
a = map(Fraction, f.split())
a = sum(map(float, a))
350
Generate a collection of "enumerated" values.

For example, Python's `enumerate` built-in function.

https://docs.python.org/3/library/functions.html#enumerate
e = enumerate(a)
351
Generate a "zipped" list z of pairs of elements from the lists a, b having the same length n.

The result z will contain n pairs.
z = zip(a, b)